Servlets & JSP 2장 정리

클라이언트가 서블릿에 대한 요청 

> 웹서버(아파치)가 서블릿을 관리하고 있는 컨테이너에게 요청

> 컨테이너(톰캣)이 HTTP Request, HTTP Response 객체를 생성

  doPost() 나 doGet()메소드 중 하나를 호출

web.xml

servlet-name을 맞춰야 한다.

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <display-name>Hello Spring</display-name>

    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>

    <servlet>
        <servlet-name>hello</servlet-name>
        <servlet-class>Ch1Servlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>hello</servlet-name>
        <url-pattern>/Serv1</url-pattern>
    </servlet-mapping>

</web-app>

Servlet 파일

RequestDispatcher를 이용하여 jsp로 넘긴다.

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class Ch1Servlet extends HttpServlet {

    public void doGet(HttpServletRequest request, HttpServletResponse response)
            throws IOException {
        
        String result =" xxx" ;
        request.setAttribute("styles", result);
        RequestDispatcher view = request.getRequestDispatcher("result.jsp");
        try {
            view.forward(request,  response);
        } catch (ServletException e) {
            e.printStackTrace();
        }
    }
    

}

xx